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RE: Question about EEb bass

To: <brass-band@xxxxxxxxxxxxxxxxxx>
Subject: RE: Question about EEb bass
From: "Rod Gibson" <rodg@xxxxxxxxxxxxxxx>
Date: Sat, 27 Nov 1999 11:52:30 -0000
Importance: Normal
In-reply-to: <Pine.SOL.4.21.9911261324460.1655-100000@primrose.csv.warwick.ac.uk>
Priority: low
Reply-to: brass-band@xxxxxxxxxxxxxxxxxx

It would be easier to straighten it out and measure it ;-)

Grandad

From: Dafydd y garreg wen 
Subject: Re: Question about EEb bass

Using the formula c (speed of sound) = f (frequency of 2nd harmonic) *
lambda (length of wavelength/tube), the total tubing would be engaged with
all 4 valves down, giving a 2nd harmonic of E natural at approximately
41.2 Hz. The speed of sound is iirc about 321 metres/second. Rearranging
to give lambda=c/f produces tube length = 321/41.2 = 7.79 metres = about
25 feet 6 inches. It will lose a bit because of the various bends in the
tube and the bell flare. Call it 25 feet to the nearest foot.

Dave Taylor
p.s. if my value of the speed of sound is wrong, then this needs to be
redone, replacing 321 with the appropriate value. 

--

References:
- Re: Question about EEb bass
  - From: Dafydd y garreg wen

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